nacosbowen(@nacosbu) 's Twitter Profile Photo

Get ready for the ultimate tech extravaganza! Bowen Tech Week is just around the corner, and we're excited to share the packed schedule of events that will inspire, educate, and connect you with the best in the tech industry!
Take a sneak peek.❤️

Get ready for the ultimate tech extravaganza! Bowen Tech Week is just around the corner, and we're excited to share the packed schedule of events that will inspire, educate, and connect you with the best in the tech industry!
Take a sneak peek.❤️
#bowentechweek
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nacosbowen(@nacosbu) 's Twitter Profile Photo

Meet the award-winning educator & TEDx speaker, Steven Loya who is shaping the future of education! This trailblazer inspires a new generation of leaders. He is a recipient of the Future Leaders Award & Edu-influencer of the Year. Don't miss out on this!❤️

Meet the award-winning educator & TEDx speaker, Steven Loya who is shaping the future of education! This trailblazer inspires a new generation of leaders. He is a recipient of the Future Leaders Award & Edu-influencer of the Year. Don't miss out on this!❤️
#bowentechweek
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nacosbowen(@nacosbu) 's Twitter Profile Photo

Get ready for a dose of wisdom and expertise. The marketing mastermind behind Cardify Africa's success, Idris Taiwo will be speaking at the Bowen Tech Week. Make deliberate efforts to be at the Bowen Tech Week!❤️

Get ready for a dose of wisdom and expertise. The marketing mastermind behind Cardify Africa's success, Idris Taiwo will be speaking at the Bowen Tech Week. Make deliberate efforts to be at the Bowen Tech Week!❤️
#bowentechweek
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Coding Ninja🥷(@Oluwatobicodes) 's Twitter Profile Photo

The President of Bowen Tech Hub is inviting you to Bowen Tech Week . Be there .👍🏾

Registration is free but compulsory
It's stars tomorrow and ends on Saturday.

Registration link : bit.ly/BTWReg

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ObaTheDev(@jeichan2007) 's Twitter Profile Photo


Writing a program to check if a string is a palindrome C++

<iostream>
<string>
bool checkPalindrome(const std::string& word) {
int left = 0;
int right = word.length() - 1;
while (left < right) {

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